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What amount of work is done if an ideal ...

What amount of work is done if an ideal gas expands from 10 L of 20 L at 2 atm pressure?

Text Solution

Verified by Experts

We know, `w=-P_(ex)(V_(2)-V_(1))`
Given: `P_(ex)=2atm,V_(1)=10L and V_(2)=20L`
`therefore w=-2(20-10)L*atm=-20L*atm`
`=-20xx101.3J=-2026J" "[because1L*atm=101.3]`
Negative value of w indicates work is done by the gas (system). therefore, the magnitude of work done by the gas (system)=2026J.
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