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1 mol of a non-ideal gas undergoes the g...

1 mol of a non-ideal gas undergoes the given change: (2 atm, 3L, 95 K)`to`(4 atm, 5L, 245 K). In this process, if increase in internal energy of the gas is 30 L`*`atm, then what will be its change in enthalpy?

Text Solution

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The change in enthalpy,
`DeltaH=Delta(U+PV)=DeltaU+Delta(PV)=DeltaU+(P_(2)V_(2)-P_(1)V_(1))`
Given: `DeltaU=30L*atm," "P_(1)=2atm," "P_(2)=4atm`,
`V_(1)=3L and V_(2)=5L`
`therefore DeltaH=30+[(4xx5)-(2xx3)]L*atm=44L*atm`.
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