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How much heat will be released when the ...

How much heat will be released when the temperature of 1 mol of water changes from `90^(@)C` to `80^(@)C`? Given: specific heat of water `4.18J*g^(-1)*K^(-1)`.

Text Solution

Verified by Experts

We know, q=`mxxcxxDeltaT`
The amount of water=1 mol. Therefore, m=18g,
`c=4.18J*g^(-1)*K^(-1)` and
`DeltaT=[(273+80)-(273+90)]K=-10K`
`therefore q=18xx4.18xx(-10)J=-752.40J`
so, for the amount of heat that will liberate when temperature of 1 mol water changes from `90^(@)C` to `80^(@)C` is 752.40 J.
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