Home
Class 12
CHEMISTRY
Bond energy of a diatomic molecule is gi...

Bond energy of a diatomic molecule is given as the change in internal energy due to dissociation of that molecule. Calculate the bond energy of `O_(2)`. Given: `O_(2)(g)to2O(g),DeltaH=498.3kJ*mol^(-1),T=298K`.

Text Solution

Verified by Experts

In the dissociation reaction of `O_(2)` molecule, `Deltan=2-1=1`
We know, `DeltaH=DeltaU+DeltanRT`
As given, `DeltaH=498.3kJ*mol^(-1),T=298K`
`therefore 498.3=DeltaU+(1xx8.314xx10^(-3)xx298)`
or, `DeltaU=495.8kJ`
`therefore`bond energy of `O_(2)` molecule=495.8`kJ*mol^(-1)`.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|119 Videos
  • CHEMICAL THERMODYNAMICS

    CHHAYA PUBLICATION|Exercise QUESTION ANSWER ZONE FOR BOARD EXAMINATION (VERY SHORT ANSWER TYPE)|26 Videos
  • CHEMICAL KINETICS

    CHHAYA PUBLICATION|Exercise EXERCISE (NUMERICAL PROBLEMS)|37 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    CHHAYA PUBLICATION|Exercise PRACTICE SET 15|15 Videos

Similar Questions

Explore conceptually related problems

Calculate the bond energy of S-F bond in SF_(6),S(g),F(g) are -1100, 275, 80 kJ*mol^(-1) respectively.

What is meant by the term bond order? Calculate the bond order of : N_(2),O_(2),O_(2)^(+) and O_(2)^(-) .

The value of DeltaH for the given reaction at 298K is -282.85 kJ*mol^(-1) . Calculate the change in intenral energy: CO(g)+(1)/(2)O_(2)(g) to CO_(2)(g) .

Assuming the reactant and product gases obey the ideal gas law, calculate the change in internal energy (DeltaE) at 27^(@)C for the given reaction: C_(2)H_(4)(g)+3O_(2)(g)to2CO_(2)(g)+2H_(2)O(l),DeltaH=-337 kcal at 27^(@)C and R=1.987 cal*K^(-1)*mol^(-1) .

Iodine molecule dissociates into atoms by absorbing light of wave length 450 nm. Calculate the kinetic energy of iodine atom if each iodine molecule absorbs one quantum radiation. (Bond energy of I_(2)=240kJ*mol^(-1) ).

In the given reaction, calculate the standard free energy change at 25^(@)C:N_(2)(g)+3H_(2)(g)to2NH_(3) [Given that, DeltaH^(0)=-91.8kJ and DeltaS^(0)=-198J*K^(-1) ]

The bond dissociation energies of three A-B bonds in AB_(3)(g) molecule are x,y and z kJ*mol^(-1) respectively. What is the bond energy of A-B bond?

The bond dissociation energies of XY, X_2 and Y_2 (all diatomic molecules) are in the reaction 1:1:0:5 and Delta H_r for the formation of XY is -200 KJ mol^(-1) what will be the bond dissociation energy of X_2 ?

Using the data provided calculate the multiple bond energy (KJ mol^(-)) of a C-=C bond in c_2H_2 consider the bond energy of a C-H bond is 350 KJ mol^(-1) 2C(s)+H_2(g)rarr C_2H_2(g), Delta H=225KJ mol^(-1) 2C(s)rarr2 C(g), Delta H=1410 KJ mol^(-1) H_2(g)rarr 2H(g), Delta H=330KJ mol^(-1)