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Assuming the reactant and product gases ...

Assuming the reactant and product gases obey the ideal gas law, calculate the change in internal energy `(DeltaE)` at `27^(@)C` for the given reaction:
`C_(2)H_(4)(g)+3O_(2)(g)to2CO_(2)(g)+2H_(2)O(l),DeltaH=-337`
kcal at `27^(@)C` and R=1.987`cal*K^(-1)*mol^(-1)`.

Text Solution

Verified by Experts

`C_(2)H_(4)(g)+3O_(2)(g)to2CO_(2)(g)+2H_(2)O(l),`
In the reaction, `Deltan=2-(1+3)=-2`
We know, `DeltaH=DeltaU+DeltanRT`
or, `-337=DeltaU-2xx1.987xx10^(-3)xx300 or, DeltaU=-335.8kcal`.
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