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Calculate (1) the enthalpy change in the...

Calculate (1) the enthalpy change in the fusion of 100 g ice at `0^(@)C` temperature and 1 atm pressure pressure (2) the enthalpy change in the vaporisation of 10g water at `100^(@)C` temperature and 1 atm pressure. Givenn : Latent heat of ice at `0^(@)C` temperature and 1 atm pressure `=6.02kJ*mol^(-1)` and latent heat of vaporisation of water at `100^(@)C` temperature=`40.4kJ*mol^(-1)`.

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(1) Latent heat of fusion of ice at `0^(@)C` temperature and 1 atm pressure=`6.02kJ*mol^(-1)`. Therefore, enthalpy of fusion of 18g ice`=6.02kJ`.
`therefore`Enthalpy of fusion 100g ice`=(6.02)/(18)xx100=33.44kJ`
`therefore`Change in enthalpy of fusion of 100g ice `=+33.44kJ`.
(2) Latent heat of vaporisation of water at `100^(@)C`
`=40.4kJ*mol^(-1)`. therefore, the enthalpy of vaporisation of 18g water=40.4 kJ
`therefore`Enthalpy of vapourisation of 10g water
`=(40.4)/(18)xx10=22.44kJ`
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