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Calculate the entropy change at 0^(@)C f...

Calculate the entropy change at `0^(@)`C for the process-
`H_(2)O(s) to H_(2)O(l)`. Given: At `0^(2)C" "C_(2)O(s)toH_(2)O(g),DeltaH=51885J*mol^(-1) and H_(2)O(l)toH_(2)O(g),DeltaH=45860J*mol^(-1)`.

Text Solution

Verified by Experts

`H_(2)O(s) to H_(2)O(g),DeltaH=51885J*mol^(-1)` . . [1]
`H_(2)O(l)toH_(2)O(g),DeltaH=45860J*mol^(-1)` . . . [2]
Subtracting equation [2] from equation [1] we get,
`H_(2)O(s)toH_(2)O(l)`,
`DeltaH=(51885-45860)=6025J*mol^(-1)`
`therefore`Change in entropy for the given process,
`DeltaS=(DeltaH)/((273+0)K)=(6025J*mol^(-1))/(273K)=22.06J*K^(-1)*mol^(-1)`.
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