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Is the vaporisation of water at 50^(@)C ...

Is the vaporisation of water at `50^(@)C` and 1 atm spontaneous? Given: For vaporisation of water at what temperature and pressure, `DeltaH=40.67kJ*mol^(-1)` and `DeltaS=108.79J*K^(-1)*mol^(-1)`.

Text Solution

Verified by Experts

We know, `DeltaG=DeltaH-TDeltaS`
`therefore DeltaG=DeltaH-TDeltaS=40.67xx10^(3)-(323xx108.79)`
`=+5530.83J*mol^(-1)`
as `DeltaG=+ve` so, vaporisation will be non-spontaneous.
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