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In the reaction, AtoB+C,DeltaH=25kJ*mol^...

In the reaction, `AtoB+C,DeltaH=25kJ*mol^(-1) and DeltaS=62.5J*K^(-1)`. At which temperature the reaction will occur spontaneously at constant pressure?

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Condition for spontaneously of a reaction at a given temperature & pressure is `DeltaG lt 0`. We know `DeltaG=DeltaH-TDeltaS`
`therefore`For spontaneous reaction, `DeltaH-TDeltaS lt 0`
or, `DeltaH lt T DeltaS or, TDeltaS gt DeltaH or, T gt (DeltaH)/(DeltaS)`
Given:`DeltaH=25xx10^(3)J and DeltaS=62.5J*K^(-1)`.
Therefore, `Tgt(25xx10^(3)J)/(62.5J*K^(-1)) or, Tgt 400K`.
So, the reaction will be spontaneous above 400`(127^(@)C)`.
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