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In the given reaction, calculate the sta...

In the given reaction, calculate the standard free energy change at `25^(@)C:N_(2)(g)+3H_(2)(g)to2NH_(3)` [Given that, `DeltaH^(0)=-91.8kJ and DeltaS^(0)=-198J*K^(-1)`]

Text Solution

Verified by Experts

We know, `DeltaG^(0)=DeltaH^(0)-TDeltaS^(0)`
`DeltaH^(0)=-91.8kJ,DeltaS^(0)=-198J*K^(-1),T=(273+25)=298K`
`therefore DeltaG^(0)=-91.8xx10^(3)-298xx(-198)=-32796J=-32.796kJ`
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