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Given (at 25^(@)C and 1 atm pressure): ...

Given (at `25^(@)C` and 1 atm pressure):
C(s, diamond)`+O_(2)(g)toCO_(2)(g),DeltaH^(0)=-393.5kJ*mol^(-1)`
C(s, graphite)`+O_(2)(g)toCO_(2)(g),DeltaH^(0)=-391.6kJ*mol^(-1)`
Find the standard heat of transition from graphite to diamond.

Text Solution

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(i) C(s, diamond)+`O_(2)(g)toCO_(2)(g),DeltaH^(0)=-393.5kJ*mol^(-1)`
(ii) C(s, graphite)`+O_(2)(g)toCO_(2)(g),DeltaH^(0)=-391.6kJ*mol^(-1)`
Subtracting equation (i) from equation (ii), we get
C(s, graphite)`to`C(s, diamond), `DeltaH^(0)=1.9kJ*mol^(-1)`
So, the heat of transition for this process is 1.9 `kJ*mol^(-1)`.
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