Explain: in a chemical reaction if (i) `DeltaH lt 0 and DeltaS gt0`, the spontaneity of the reaction is independent of temperature. (ii) `DeltaH gt0` and `DeltaS gt0`, the spontaneity of the reaction is dependent of temperature.

How does the spontaneity of an exothermic reaction depend on temperature when (i) DeltaS gt0 and (ii) DeltaS lt0 ?

How does the spontaneity of an endothermic reaction depend on temperature when (i) DeltaS gt0 and (ii) DeltaS lt0 ?

At a given temperature and pressure, for a chemical reaction DeltaH lt 0 & DeltaS lt 0 . Is the spontaneously of this reaction dependent upon temperature? If it depends and if the reaction reaches equilibrium at a temperature of T_(e), then will the reaction be spontaneous below or above T_(e) ?

Give an example of a chemical reaction where DeltaH = Delta U .

At 25^(@)C and 1 atm pressure, for the reaction 3O_(2)(g)to2O_(3)(g)," "DeltaH=286kJ and DeltaS=-137.2J*K^(-1) . Is this reaction spontaneous? Does the spontaneity of thir reaction depend on temperature? Is the reverse reaction spontaneous ? If so, then why? does the spontaneity of the reverse reaction depend on temperature?

A reaction is spontaneous at a temperature of 300K, but it is non-spontaneous at a temperature of 400K. If DeltaH and DeltaS for the reaction do not depend on temperature, then-

Can DeltaH can be taken as a sole criterion of the spontaneity of a reaction? Justify with example.

Which of the following conditions favours the spontaneity of a reaction at a constant temperature and pressure? DeltaH gt0, DeltaH lt 0, DeltaS gt0, DeltaS lt 0 .

If the value of DeltaH and DeltaS are of following type, then at what condition a reaction will occur spontaneously? (i) DeltaH gt0 and DeltaSgt0 (ii) DeltaH lt0 and DeltaS gt0