Assuming experimental conditions are the same, compare `(DeltaH-DeltaU)` values for the gives reaction:
(1) `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(l)`
(2) `H_(2)(g)+(1)/(2)O_(2)(g)toH_(2)O(g)`.

Explanation

In case of reaction (1), `Deltan=0-(1+(1)/(2))=-(3)/(2)`
Therefore, `DeltaH-DeltaU=DeltanRT=-(3)/(2)RT`
In case of reaction (2), `Deltan=1-(1+(1)/(2))=-(1)/(2)`
Therefore, `DeltaH-DeltaU=DeltanRT=-(1)/(2)RT`
Hence, the magnitude of `(DeltaH-DeltaU0` is greater is case of (2).