Latent heat of fusion of ice at `0^(@)C` is 80cal/g. calculate the olar entropy change for the fusion process.

Explanation

We know, `DeltaS=(DeltaH_(f))/(T_(f))`, where `DeltaH_(f)=`latent heat of fusion of a substance and `T_(f)=`its melting point.
Now, `DeltaH_(f)=60cal*g^(-1)xx18g=1440` cal.
`therefore DeltaS=(1440)/(273)cal*K^(-1)=5.27cal*K^(-1)`