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In a process, 600J of heat is absorbed b...

In a process, 600J of heat is absorbed by a system and 300J of work is done by the system. Calculate the change in internal energy of the system.

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Verified by Experts

Given: `q=+600J,w=-300J.` so, change in internal energy, `DeltaU=q+w=(600-300)J=300J`.
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