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Latent heat of vaporisation of water at ...

Latent heat of vaporisation of water at normal boiling point is `40.75kJ*mol^(-1)`. Calculate the change in entropy of vaporisation.

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Given: `DeltaH_(vap)=40.75kJ*mol^(-1),T_(b)=100^(@)C=373K`
`therefore`Change in entropy of vaporisation,
`DeltaS=(DeltaH_("vap"))/(T_(b))=(40.75xx10^(3)J*mol^(-1))/(373)=109.25J*mol^(-1)`.
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