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Calculate the change in internal energy ...

Calculate the change in internal energy of the gas when it expands from 2L to 8L at a constant pressure of 2 atm absorbing 400 J of heat in the process. (1L`*atm=101.35J`).

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We know, `w=-P_(ex)(V_(2)-V_(1))`
`therefore w=-2(8-2)=-12L*atm=-12xx101.3J=-1215.6J`.
According to the 1st law of thermodynamics, `DeltaU=q+w`
Given that `q=400J`
`therefore DeltaU=(400-1215.6)J=-815.6J`
`therefore`Change in internal energy of the gas=-815.6J.
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