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Calculate the work done for a reversibl...

Calculate the work done for a reversible isothermal compression of 1 mol ideal gas 20 L to half of its volume at 400K `[R=8.314J*K^(-1)*mol^(-1)]`.

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Work done in an isothermal reversible compression,
`w=-nRTxx2.303"log"(V_(2))/(V_(1))[V_(2)ltV_(1)]`
`therefore w=-1xx8.314xx400xx2.303"log"(10)/(20)J=2.305kJ`
`therefore` The around of work done=2.305 kJ.
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