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Given: C+O(2)toCO(2),DeltaH^(0)=-xkJ 2...

Given: `C+O_(2)toCO_(2),DeltaH^(0)=-xkJ`
`2CO+O_(2)to2CO_(2),DeltaH^(0)-y` kJ
Heat of formation of carbon monoxide will be-

A

`(y-2x)/(2)`

B

`y+2x`

C

`2x-y`

D

`(2x-y)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`C+O_(2) to CO_(2),DeltaH^(0)=-x` kJ . . . [1]
`2CO+O_(2)to2CO_(2),DeltaH^(0)=-y` kJ . . .[2]
Subtracting equation [2] from the equation obtained by multiplying equation [1] by 2, we have
`2C+O_(2) to 2C,DeltaH=(y-2x)kJ`
`therefore`Heat of formation of `CO=((y-2x)/(2))kJ*mol^(-1)`
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