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The enthalpy of vaporisation of a certai...

The enthalpy of vaporisation of a certain liquid at its boiling point off `35^(@)C` is `24.64kJ*mol^(-1)`. The value of change in entropy for the process is-

A

`704J*K^(-1)*mol^(-1)`

B

`80J*K^(-1)*mol^(-1)`

C

`24.64J*K^(-1)*mol^(-1)`

D

`7.04J*K^(-1)*mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaS_("vap")=(DeltaH_("vap"))/(T_(b))=(24.64xx10^(3)J*mol^(-1))/((273+35)K)`
`=80J*K^(-1)*mol^(-1)`
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