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Calculate the change in entropy for the ...

Calculate the change in entropy for the following process : 2 mol of `N_(2)` (l , 1 atm, `-195.6^(@)C) to 2 " mol of " N_(2) (g, 1 " atm " -195.6^(@)C)` [Given that, change in molar enthalpy for the vaporisation of `N_(2)= 5.586 " kJ mol"^(-1)`]

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`Delta S= ((DeltaH_("vaporisation")) " for 2 mol " N_(2)(l))/(T_(b))`
`=(2xx5.586xx10^(3))/((273-195.6))J. K^(-1) = 144.34 J. K^(-1)`
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