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At 298 K, the equilibrium constant of a ...

At 298 K, the equilibrium constant of a reaction is `1.8xx10^(-7)`. If `Delta H^(0)` of the reaction is 28.6 kJ, calculate the value of `Delta S^(0)`.

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`Delta G^(0)= Delta H^(0)- T Delta S^(0) = (28.6xx10^(3)- 298xx Delta S^(0))J`
Again, `Delta G^(0)= - RT " ln " K = - 2.303 " RT log " K`
`28.6xx10^(3)- 298xx Delta S^(0)= - 2.303xx8.314xx298 " log " (1.8xx10^(-7))`
`therefore Delta S^(0) = - 33.12 J. K^(-1)`
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