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At 986^(@)C, 3 mol of H(2)O(g) and 1 mol...

At `986^(@)C`, 3 mol of `H_(2)O(g)` and 1 mol of CO(g) react with each other according to the reaction, `CO(g)+H_(2)O(g)hArr CO_(2)(g)+H_(2)(g)`. At equilibrium, the total pressure of the reaction mixture is found to be 2.0 atm. If `K_(c)=0.63` (at `986^(@)C`), then at equilibrium find (1) the number of moles of `H_(2)(g)`, (2) the partial pressure of each of the gases.

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