Home
Class 12
CHEMISTRY
At a particular temperature and 0.50 atm...

At a particular temperature and 0.50 atm pressure, `NH_(3)(g)` and some amount of solid `NH_(4)HS` are present in a closed container. Solid `NH_(4)HS` dissociates to give `NH_(3)(g)` and `H_(2)S(g)`. At equilibrium, the total pressure of the reaction-mixture is found to be 0.84 atm. find the value of equilibrium constant of this reaction at that temperature.

Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|153 Videos

  • EQUILIBRIUM

    CHHAYA PUBLICATION|Exercise QUESTION ANSWER ZONE FOR BOARD EXAMINATION (very short answer type)|30 Videos

  • ENVIRONMENTAL CHEMISTRY

    CHHAYA PUBLICATION|Exercise PRACTICE SET 14(Answer the following questions)|6 Videos

  • GENERAL PRINCIPLES AND PROCESSES OF ISOLATION OF ELEMENTS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 6|10 Videos