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A 0.1 (M) solution of acetic acid is 1.3...

A 0.1 (M) solution of acetic acid is 1.34% ionised at `25^(@)`. Calculate the ionisation constant of the acid.

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We know, ionisation constant of a weak monobasic acid (e.g., `CH_(3)COOH`) is `K_(a)=(alpha^(2)c)/(1-alpha)`, wehere `alpha`=degree of ionisation and c=initial concentration of the acid solution.
As `alpha=(1.35)/(100)=1.35xx10^(-2) and c=0.1(M)`,
`K_(alpha)=(alpha^(2)c)/(1-alpha)=((1.34xx10^(-2))^(2)xx0.1)/((1-1.34xx10^(-2)))=1.82xx10^(-5)`
`therefore`At `25^(@)C`, ionisation constant of `CH_(3)COOH=1.82xx10^(-5)`.
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