The reaction `Fe_(2)O_(3)(s)+3CO(g)to 2Fe(s)+3CO_(2)(g)` is carried out separately in a closed vassel and in an open vesel in which case do you expect a higher yield of `CO_(2)(g)`?

Explanation

If the reaction `Fe_(2)O_(3)(s)+3CO(g) to 2Fe(s)+3CO_(2)(g)` is carried out in a closed vessel, an equilibrium is established between the reactants and the products. As a result, the reaction vessel always contains a mixture of reactants and products. On the other hand, if the reaction is carried out in an open vessel, `CO_(2)(g)` formed in the reaction diffuses out from the vessel and mixes with the air and does not have the opportunity to react with Fe(s). as a result, the reaction becomes irreversible and goes to completion. at the end of the reaction, the vessel only contains Fe(s). since the reaction reaches completion in an open vessel, the yield of `CO_(2)(g)` will be more in this condition.