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At a given temperature, for the reaction...

At a given temperature, for the reaction `AhArrB`, the rate constant `(k_(f))` of the forward reaction is greater than that of the backward reaction `(k_(b))`. Is the value of equilibrium constant (K) for this reaction greater than, less than or equal to 1?

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The equilibrium constant (K) of a reaction
`=("Rate constant of the forward reaction")/("Rate constant of the backward reaction")=(K_(f))/(K_(b))`
Given: `K_(f) gt K_(b)`. Therefore `Kgt1`.
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