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At a particular temperature, the followi...

At a particular temperature, the following reaction is carried out with 1 mol of A(g) and 1 mol of B(g) in a closed vessel: `A(g)+4B(g)hArr 4B_(4)(g)`.
Will the equilibrium concentration of `AB_(4)(g)` be higher thn that of A(g)?

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According to the given equation of the reaction, 1 mol of `AB_(4)` forms due to the reaction between 1 mol of A and 4 mol of B.
Suppose, the concentration of `AB_(4)` at equilibrium of the reaction is x `mol*L^(-1)`. So, according to the given equation, the concentration of A and B at equilibrium will be (1-x) `mol*L^(-1)` and (1-4x) `mol*L^(-1)`, respectively. at equilibrium, if the concentration of `AB_(4)` was greater than that of A, then x would be greater than (1-x), i.e., `x gt1 -x or, x gt0.5`.
If x was greater than 0.5 , then the concentration of B would be negative. this is impossible. therefore, the concentration of `AB_(4)` can never be greater than that of A.
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