We know, `DeltaG^(0)=-RTlnK_(c) and DeltaG^(0)=-RTlnK_(p)`. Therefore in case of a reaction occurring in gaseous phase at a given temperature, `DeltaG^(0)` is the same evenn if the values of `K_(p) and K_(c)` are different. Is the statement true? Given reasons.

Explanation

The statement is not true. In the equation `DeltaG^(0)=-RTlnK_(c)`, the concentration of each of the reactants and products at standard state is takenn as 1(M). On the other hand, in the equation `DeltaG^(0)=-RTlnK_(p)`, the partial pressure of each of the reactants and products at standard state is taken as 1 atm. therefore, the different values of `DeltaG^(0)` will be obtained from these two equations.