In the reaction `I_(2)+I^(-)toI_(3)^(-)`, which one acts as a Lewis base?

Explanation

In the reaction between `I^(-) and I_(2),I^(-)` ion donates an electron pair to `I_(2)` molecule, resulting in the formation of `I_(3)^(-)` ion `[I_(2)+I^(-) +I_(3)^(-)]`. Therefore, `I^(-)` ion acts as a lewis base in this reaction.