Find out the value of `K_(p)//K_(c)` for the reaction `PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)`, at 298K, consider the unit of concentration is `mol*L^(-1)` and the unit of pressure is atm.

Explanation

We know, `K_(p)=K_(c)(RT)^(Deltan)`
For the given reaction, `Deltan=(1+-1)=1`
Thus, `K_(p)=K_(c)xxRT" or ", (K_(p))/(K_(c))=RT`
`=0.0821L*atm*mol^(-1)K^(-1)xx298K`
`=24.465L*atm*mol^(-1)`.