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At 25^(@), K(sp) for PbCl2 is 1.6xx10^(-...

At `25^(@)`, `K_(sp)` for `PbCl_2` is `1.6xx10^(-5)` in water. At the same temperature, the amount of `PbCl_2` (molar mass = 278.19 `g*mol^(- 1))` that remains in dissolved state in 100mL of a saturated solution of `PbCl_2` is-

A

0.28g

B

0.44g

C

0.17g

D

0.35g

Text Solution

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The correct Answer is:
B
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