`AB(g)+1/2B_2(g) rarr AB_2(g)`, equilibrium constant `=K_1`
`2AB_2(g)rarr2AB(g)+B_2(g)`, equilibrium constant `=K_2`.
Find the relation between `K_1` and `K_2`

For the reaction N_2 (g) + O_2 (g) overset(rightarrow)(leftarrow) 2NO (g) the equilibrium constant is K_1 . The equilibrium constant is K_2 for the reaction , 2NO(g) + O_2 (g) overset(rightarrow)(leftarrow) 2NO_2 (g). What is K for the reaction, NO_2 (g) overset(rightarrow)(leftarrow) 1/2N_2(g)+ O_2 (g) -

For the reactions. N_2(g)+3H_2(g)hArr 2NH_3(g),N_2(g)+O_2hArr2NO(g) & H_2(g)+1/2O_2(g)hArrH_2O(g) if the equilibrium constant are K_1,K_2 and K_3 respectively, then the equilibrium constant for the reaction 4NH_3(g)+5O_2(g)hArr4NO(g)+6H_2O(g) is

If equilibrium constant for N_2(g)+O_2(g)

For the reaction, N_2(g)+O_2(g)hArr2No(g) equilibrium constant is K_1 . The equilibrium constant is K_2 for the reaction. 2NO(g)+O_2(g)hArr2NO_2(g) . What is K for the reaction, NO_2(g)hArr1/2N_2(g)+O_2(g) -

The equilibrium constant of the following equilibria SO_(2)(g)+(1)/(2)O_(2)(g)hArr SO_(3)(g) 2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g) are given by K_(1) and K_(2) respectively. Find the relation between K_(1) and K_(2) .

For the reaction, 2NO_2(g) +1/2O_2 iff N_2O_5(g) if the equilibrium constant is K_p , then the equilibrium constant for the reaction 2N_2O_5(g) iff 4NO_2 + O_2(g) would be

If the equilibrium constant for N_2(g) + O_2(g) iff 2NO(g) is K, the equilibrium constant for 1/2N_2(g) +1/2 O_2(g) iff NO(g) will be:

Find out the equilibrium constant for the reaction, XeO_(4)(g)+2HF(g)hArr XeO_(3)F_(2)(g)+H_(2)O(g) consider K_(1) as the equilibrium constant for the reaction, XeF_(6)(g)+H_(2)O(g)hArr XeOF_(4)(g)+2HF(g) and K_(2) as the equilibrium constant for the reaction, XeO_(4)(g)+XeF_(6)(g) hArr XeOF_(4)(g)+XeO_(3)F_(2)(g) .

The equilibrium constant for the reaction N_2(g) +O_2(g)iff2NO is K_1 and the equilibrium constant for the reaction 2NO(g)+O_2(g)iff2NO_2(g) is K_2 What will be the equilibrium constant for the reaction N_2(g)+2O_2(g)iff2NO_2(g)