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For the reaction, A(g)+B(g)toC(g)+D(g) o...

For the reaction, `A(g)+B(g)toC(g)+D(g)` occuring in a closed vessel of 1L volume, the value of equilibrium constant is 16 at a particular temperature. If the number of moles of each of the constituents be 1, then in which direction will the reaction occur to a greater extent to attain equilibrium? Also, calculate the molar concentrations of B(g) and D(g) at equilibrium

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`Q_c=([C][D])/([A][B])=(1xx1)/(1xx1)=1`
So, `Q_cltK_c` Hence, the reaction will occur to a greater extent in the forward direction.
`A(g)+B(g)toC(g)+D(g)`
Conc. In equilibrium :`(1-prop)(1-prop)(1+prop)(1+prop)`
`K_c=((1+prop)^2)/((1-prop)^2)` or `(1+prop)/(1-prop)=sqrtK_c=sqrt16=4`
`:.` At equilibrium [B(g)]`=1-0.6=0.4mol*L^(-1)` and `[D(g)]=1.6mol*L^(-1)`
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