At a given temperature, `NH_3` gas is in a state of equilibrium with `N_2` and `H_2` gases in a closed container. If the partial pressures of `N_2` and `H_2 `in the mixture are 1.34 and 0.67 atm respectively and the total pressure of the reaction mixture is 4.67 atm, then determine the value of `K_p` for the reaction : `N_2(g)+3H_2(g)

Explanation

Total pressure of the mixture = 4.67 atm. In the mixture,
`p_(N_2)=1.34atm,p_(H_2)=0.67atm`
`pNH_3=[4.67-(1.34+0.67)]=2.66atm`

`N_2+3H_2 `K_p=(p_(NH_3)^2)/(p_(N_2)xxp_(H_2)^3)=((2.66)^2)/(1.34xx(0.67)^3)=17.56atm^(-2)`