Calculate the value of `K_P` for the reactfon, `PCl_5(g)hArrPCl_3(g)+Cl_2(g)` at 298K [Given : `/_\G_f^0(Cl_2)=0,(/_\G_f^0)(PCl_3)=-68.42kcal.mol^(-1)` and `/_\G_f^0(PCl_5)=-77.6 kcal.mol^(-1)`]

Explanation

For the given reaction, `/_\G^0=2/_\G_f(NO_2)^0-/_\G_(f(N_2O_4)^0`
`=(2xx50-100)kJ=0`
We know, `/_\G^0=-RTinK_p` or `0=-RTInK_p`
`:.K_p=1`
In the mixture, total number of moles of `N_2O_4` and
`NO_2=(5+5)mol=10mol`
So, in the mixture, `p_(N_2O_4)=5/(10)xx20"bar"=10"bar"`
`p_(NO_2)=5/(10)xx20"bar"=10"bar"`
`:.Q_p=(p_(NO_2)^2)/(p_(N_2O_4)^2)=((10^2)/(10)`bar=10bar