In 0.01(M) acetic acid solution, pH = 3.37. What is the degree of ionisation of the acid?

Explanation

8.4g of `CH_3COONa-=(8.2)/(82)-=0.1` mol of `CH_3COONa`
`[CH_3COONa]=(0.1)/(1)=0.1(M)`
`pH=pK_a+log([CH_3COONa])/([CH_3COOH])=4.74+log(0.1)/(0.1)=4.74`
`:.[H_3O^+]=10(-pH)=10^(-4.74)=1.81xx10^(-5)(M)`
or `propc=1.81xx10^(-5)(M)` or `propxx0.1=1.81xx10^(-5)(M)`
`:.prop=1.81xx10^(-4)`
Before adding `CH_3COONa`
`prop=sqrt((K_a)/(c))=sqrt((1.8xx10^(-5))/(0.1))=0.0134`
Therefore, change in degree of ionisation
`=0.0134-1.81xx10^(-4)=1.33xx10^(-2)`