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Calculate the degree of hardness of a sa...

Calculate the degree of hardness of a sample of hard water which is found to contain 72 mg of `"MgSO"_(4)` per kg of water.

Text Solution

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Now, 1 kg or `10^(3)` g of water contains 72 mg `"MgSO"_(4)`
`therefore " "10^(6)` g of water contains `72xx10^(3)` mg = 72 g `"MgSO"_(4)`
Now, 60 g `"MgSO"_(4) equiv 50 g CaCO_(3)`
or, 72 g `"MgSO"_(4) equiv (50xx 72)/(60) g CaCO_(3) = 60 g CaCO_(3)`
Thus, the degree of hardness of that sample = 60 ppm.
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