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Determine the strength of '10 volume H(2...

Determine the strength of '10 volume `H_(2)O_(2)`' solution in
(1) gram per litre,

Text Solution

Verified by Experts

2`H_(2)O_(2)(68 g) rarr 2H_(2)O + O_(2) [ 22.4 L "at STP" ] `
(1) Now, 10 volume `H_(2)O_(2)` solution means that at STP 10 mL `O_(2)` is obtained from 1 mL of this solution.
`therefore` 22400 mL `O_(2)` at STP is Obtained from
`(22400)/(10) = 240 " " "mL" H_(2)O_(2)`
`therefore` 2240 mL of `H_(2)O_(2)` solution contains 68g of `H_(2)O_(2)`.
`therefore " "1000 " mL" H_(2) O_(2)` solution = `(68 xx 1000)/(2240) = 30.36g " "H_(2)O_(2).`
So, strength of 10 volume `H_(2)O_(2)` solution = 30.36g `"g.L"^(-1)`.
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