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Determine the volume strength of 1.5 (N)...

Determine the volume strength of 1.5 (N) `H_(2)O_(2)`.

Text Solution

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1L of 1.5 (N)`H_(2)O_(2)` solution contains 1.5`xx`17 = 25.5 g .
`therefore` 1 mL of 1.5(N) `H_(2)O_(2)` solution contains 25.5/1000 = 0.0255g .
Now 68 g `H_(2)O_(2)` liberates 22400 ml `O_(2)` STP.
`therefore 0.0255g H_(2) O_(2)` liberates 22400`xx(0.0255)/(68)` = 8.4 mL `O_(2)` at STP.
Therefore, volume strength of 1.5 (N)`H_(2)O_(2)` solution = 8.4 .
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