Home
Class 12
CHEMISTRY
Determine the volume strength of a 6.07%...

Determine the volume strength of a 6.07% `H_(2)O_(2)` solution.

Text Solution

Verified by Experts

6.07% `H_(2)O_(2)` solution means 100 mL of the solution contains 6.07 g of `H_(2)O_(2)`.
`therefore" " `1 mL solution contains `(6.07)/(100) = 0.0607 " g "H_(2)O_(2)` .
`2H_(2)O_(2)(68g) rarr 2H_(2)O + O_(2)` [ 22400 mL at STP]
Now, 68 g `H_(2)O_(2)` liberates 22400 mL `O_(2)` at STP.
`therefore " " 0.0607 "g " H_(2)O_(2)` solution produces 20 mL `O_(2)` at STP.
Hence, volume strength of 6.07% `H_(2)O_(2)` solution is '20 volume'.
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    CHHAYA PUBLICATION|Exercise WARM UP EXERCISE|119 Videos

  • HYDROGEN

    CHHAYA PUBLICATION|Exercise QUESTION-ANSWER ZONE FOR BOARD EXAMINATION (VERY SHORT ANSWER TYPE)|30 Videos

  • HYDROCARBONS

    CHHAYA PUBLICATION|Exercise PRACTICE SET 13|16 Videos

  • MODEL QUESTION PAPER

    CHHAYA PUBLICATION|Exercise Answer the following question (set-3)|130 Videos

Similar Questions

Explore conceptually related problems

Determine the volume strength of 1.5 (N) H_(2)O_(2) .

Calculate the volume strength of 1% H_(2)O_(2) solution.

Determine the volume strength of 1(N) H_(2)O_(2) .

What will be the "volume strength of 6.07% H_2O_2 solution calculate it.

If 4ml O_2 is obtained at 1.5atm pressure and 25^@C from 1 ml H_2O_2 solution. Then find the volume strength of H_2O_2 solution.

Determine the strength of '10 volume H_(2)O_(2) ' solution in (3)percentage strength.

Determine the strength of '10 volume H_(2)O_(2) ' solution in (2) normality and

20 mL of a H_(2)O_(2) solution after acidification required 20 mL of N/10 KMn O_(4) solution for complete oxidation. Calculate the percentage and volume strength of H_(2)O_(2) solution.

.The volume strength of 10NH_2O_2 is

The volume strength of 1.5NH_2O_2 solution is