Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with
acidified water and

Explanation

In acidified water: The `H^(+)` ions react with `Al(OH)_(3)` to from `Al^(3+)`(aq) ions adn `H_(2)O` .Therefore , in acidic water, `"AlCl"_(3)` exists as `Al^(3+) `(aq) and `Cl^(-)`(aq) ions.
`"AlCl"_(3)(s) overset("acidified"H_(2)O)(rarr) Al^(3+) (aq) + 3Cl^(-) (aq)`
Potassium chloride, KCl simply dissociates to give `K^(+)`(aq) and `Cl^(-)`(aq) ions.
KCl(s)`overset("acidified water")(rarr) K^(+)(aq) + Cl^(-)`(aq)