Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with
alkaline water? Write equations wherever necessary.

Explanation

In alkaline water: `Al(OH)_(3)` reacts with `OH^(-)` ions to form soluble tetrahydroxoaluminate complex or meta-aluminate ion (`AlO_(2)^(-)`).
`AlCl_(3)(s) + 4OH^(-) (aq) rarr[Al(OH)_(4)]^(-) (aq) + 3Cl^(-) (aq) rarr underset("Tetrahydroxoaluminate complex")(Al_(2)^(-) (aq) + 2H_(2)O(l))`
KCl does not react and dissociate to give `K^(+)`(aq) and `Cl^(-)`(aq) ions.