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Determine the volume (in litre) of O(2) ...

Determine the volume (in litre) of `O_(2)` obtained at STP when 0.1 litre of 2(M)`H_(2)O_(2)` solution is decomposed.

Text Solution

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`2H_(2)O_(2) rarr 2H_(2)O + O_(2)`
`(2 xx 34)`g = 68g `" "`22.4L(at STP)
Now, 1L 1(M) `H_(2)O_(2)` = 34g of `H_(2)O_(2)`
`therefore` 1L 2(M)`H_(2)O_(2) = (2 xx 34)`g of `H_(2)O_(2)`
`therefore` 0.1L 2(M) `H_(2)O_(2) = (2 xx 34 xx 0.1)`g of `H_(2)O_(2)` = 6.8g of `H_(2)O_(2)`
Again at STP, 68g of `H_(2)O_(2)` produces 22.4L of `O_(2)`.
`therefore` 6.8g of `H_(2)O_(2)` produces `(22.4)/(68) xx` 6.8L of `O_(2)`
`" "= 2.24`L of `O_(2)`
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