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Solubility of ZnSO(4) in water is x mol...

Solubility of `ZnSO_(4)` in water is x ` mol * L^(-1)` . Give the mathematical expression of solubility product of the compound .

Text Solution

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`ZnSO_(4) (s) hArr Zn^(2+) (aq) + SO_(4)^(2-) (aq) `
`therefore K_(sp) = [Zn^(2+)] xx [SO_(4)^(2-)]`
Since , solubility of `ZnSO_(4)` in water is x `mol * L^(-1)` , so `[Zn^(2+)] = [SO_(4)^(2-)] = x mol * L^(-1)`
`therefore K_(sp) = x xx x = x^(2)`
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