How many hydrogen atoms are present in 32 amu of methane ?

Explanation

Atomic mass of methane=16
1 amu `=1.6605 xx 10^(-24)`
`therefore 32 amu = 5.3136 xx 10^(-23)g`
hydrogen atom present in 16 g methane is `6.022 xx 10^(23)xx4`
`therefore` hydrogen atom present in `5.3136 xx 10^(-23)g` methane
`=(6.022 xx 10^(23)xx4xx5.3136xx10^(-23))/(16)=8`
Altomic mass of methane =16
so, the mass of one methane molecule 16 amu
`therfore` methane molecule present in 32 amu mass is =2.
`therefore` hydrogen atom present in 2 mehane molecule
`=2xx4=8`