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Determine the electromotive force of the...

Determine the electromotive force of the following galvanic cell at `25^(@)C`
`Pt|H_(2)("10 atm")|HCl|H_(2)("5 atm")|Pt`

Text Solution

Verified by Experts

`{:("Anode reaction: "H_(2)("g, 10 atm")" "rarr" "2H^(+)(aq)+2e),("Cathode reaction: "2H^(+)(aq)+2e" "rarr" "H_(2)("g, 5 atm")),(bar(" Cell reaction: "H_(2)("g, 10 atm")" "rarr" "H_(2)("g, 5 atm")" ")):}`
Here, 2 mol of electrons are involved in the cell reaction, so n = 2.
Hence EMF of the cell at `25^(@)C`,
`E_("cell")=E_("cell")^(@)-(0.059)/(2)log.(5)/(10)=E_("cathode")^(@)-E_("anode")^(@)+(0.059)/(2)log2`
`=(0-0)+0.0089=0.0089V`
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