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Calculte the standard free energy change...

Calculte the standard free energy change for the reaction occurring in a Daniell cell `(E_("cell")^(@)=1.10V)`.
`Zn(s)+Cu^(2+)(aq)rarrZn^(2+)(aq)+Cu(s)`

Text Solution

Verified by Experts

`{:("Anode reaction: "Zn(s)" "rarr" "Zn^(2+)(aq)+2e),("Cathode reaction : "Cu^(2+)(aq)+2e" "rarr" "Cu(s)),(bar(" Cell reaction: "Zn(s)+Cu^(2+)(aq)" "rarr" "Zn^(2+)(aq)+Cu(s))):}`
As 2 mol electrons are involved in the cell reaction, n = 2.
Therefore, the standard free energy change,
`DeltaG^(@)=-nFE^(@)`
`=-(2xx96500xx1.10)=-212300J,C-212300J`
`=-212.3" kJ "[because "1 volt - coulomb = 1 joule"]`
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