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Distance between the electrodes of a con...

Distance between the electrodes of a conductivity cell is 1.75 cm, and the cross - sectional area of each electrode is `4cm^(2)`. If the cell is filled wich 0.5(M) solution of an electrolyte, then the resistance of the cell becomes 25 ohm. Calculate the specific conductance of the solution.

Text Solution

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Specific conductance, `kappa =((1)/(R)) xx(l)/(A)`
Putting, l = 1.75, A = `4.0cm^(2)` and R = 25 ohm into the above equation, we have
Specific conductance `=((1)/(25))xx(1.75)/(4)="0.0175 ohm"^(-1)."cm"^(-1)`
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