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Distance between the two electrodes of a...

Distance between the two electrodes of a conductivity cell is 1 cm, and the cross - sectional area of each electrode is `2cm^(2)`. If the cell is filled with `"50 g,L"^(-1)` KCl solution, resistance of the cell appears to be 7.25 ohm. What is the molar conductivity of the solution?

Text Solution

Verified by Experts

Specific conductance, `kappa =((1)/(R))xx(l)/(A)`.
Putting : R = 7.25 ohm and l = 1 cm, `A=2cm^(2)` in the above relation gives
`kappa =(1)/(7.25)xx(1)/(2)="0.0689 ohm"^(-1)."cm"^(-1)`
Molarity of KCl solution `=(50)/(74.5)="0.6711" mol"^(-1)`
`[because " Molar conductivity, "Lambda_(m)=kappa xx(1000)/(M)=0.0689xx(1000)/(0.6711)]`
`=102.67" ohm"^(-1)."cm"^(2)."mol"^(-1)`
Therefore, molar conductivity of the KCl solution `="102.67 ohm"^(-1)."cm"^(2)."mol"^(-1)`
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